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11x^2-x-12=0
We add all the numbers together, and all the variables
11x^2-1x-12=0
a = 11; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·11·(-12)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-23}{2*11}=\frac{-22}{22} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+23}{2*11}=\frac{24}{22} =1+1/11 $
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